THE ROOT OF THE EQUATION BY ITERATION METHOD

/*PROGRAM TO FIND THE ROOT OF THE EQUATION BY ITERATION METHOD*/

#include<stdio.h>

#include<conio.h>

#include<math.h>

float f(float x)

{

return(1/sqrt(1+x));

}

void main()

{

int i,n;

float x0,x1,e;

clrscr();

printf(“Enter he value of x0,n,e::  \n”);

scanf(“%f%d%f”,&x0,&n,&e);

for(i=1;i<=n;i++)

{

x1=f(x0);l

printf(“\n Root is  =%f”,x1);

if(fabs(x1-x0/x1)<e)

{

printf(“\n Current root is =%f”,x1);

break;

}

x0=x1;

}

getch();

}

/*

OUTPUT

Enter the value of x0,n,e::

5

8

.005

Root is = 0.408248

Root is = 0.842676

Root is = 0.736674

Root is = 0.758824

Root is = 0.754030

Root is = 0.755060

Root is = 0.754838

Root is = 0.754886

*/